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42k^2-86k+4=0
a = 42; b = -86; c = +4;
Δ = b2-4ac
Δ = -862-4·42·4
Δ = 6724
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{6724}=82$$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-86)-82}{2*42}=\frac{4}{84} =1/21 $$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-86)+82}{2*42}=\frac{168}{84} =2 $
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